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STRUCTURES ][ 



Design of a bolted SPLICE Connection P&A 351

SAMPLE Problem: ============== Design a bolted connection, that achieves a splice between two members ( 2 angles pre selected by designer) A tension force of 54 kips is to be transmitted The intention is to use a single row ( single row pre selected by designer) of A325F bolts ( A325 F bolts pre selected by designer) and a splice plate.
1. bolted connection 2. splice connection 3. two (2) pairs of angles 4. tension connection 5. tension force 54 kips 6. single row of bolts 7. A 325 F bolts A 325 = high-strength bolt F = denotes bolt for which the limiting resistance is that of friction P&A 342 = definition P&A 344 = Capacity

1. Size of bolts a. diameter of the bolts b. length of the bolts 2. Number of bolts a. single row pre-selected 3. Size of the angles a. leg 1 b. leg 2 c. thickness 4. Size of splice plate a. thickness b. width c. length

1. Loading Condition of Bolt: ====================== Bolts are in Double Shear (see PA 343)

2. Capacity of Bolts: =============== Table 11.1 P&A 344 A 325 F - Friction - given D - Double Shear 5/8" = 10.4 kips / bolt 3/4" = 15.0 kips 7/8" = 20.4 kips 1" = 26.7 kips

3. Number of Bolts: =============== N = P / F P = 54 kips tension force given F = capacity of bolt from T11.1 P&A 344 5/8" = 54/10.4 = 5.19 = 6 3/4" = 54/15 = 3.60 = 4 7/8" = 54/20.4 = 2.65 = 3 1" = 54/26.7 = 2.02 = 3 6 bolts per leg make a long joint 3 bolts make a shorter joint - design issue 4. Edge Distance for rolled shapes: ========================= Table 11.2 P&A 345 Angle = rolled edge Edge Distance Angle Size 1" bolt = 1.25" 2.5" 7/8" = 1.125" 2.25" 3/4" = 1 2." 5/8" = 0.875" 1.75" Leg Angle Size 2.5"

5. Gage g for Angles =============== Table 11.4 P&A 347 g = edge distance for angle 2.5 " angle gage 1 3/8 1.375 edge distance 1 1/4 1.250 --------------------------------------------------------------------------- 2.625 2.5" angle will not work try 3" angle gage 1 3/4 1.75 edge distance 1 1/4 1.25 ----------------------------------------------------------------------------- 3.00 works 1" bolts require a 3.0 inch angle 3/4" bolts require a 2.5 inch angle 7/8" bolts require a 2.5 inch angle 5/8" bolts require a 3.0 inch angle

7. Answer: ======== Due to design and construction considerations (all 3/4" bolts) we selected 4 bolts 3/4" on each side of the joint
8. Stress on unreduced area: ==================== Table 8.1 P&A 267 Ft = 0.60 Fy Ft = 0.60 x 36 ksi Ft = 22 ksi

9. Unreduced Area ============= A = P/Ft A = 54 / 22 A = 2.46 sq.in. per pair A1= 2.46 / 2 A1= 1.23 sq in per angle 10. Double Angle ============= Table 4.2 P&A 174 (Book typo Table 4.3 P&A 175) Area = 1.23 sq. in. 3 x 2 x 5/16 selected Area = 1.46 sq. in. based on stress through entire section and edge distance and pitch

11. Angle Design-Net Area:
====================
based on the previous section
and also considering the net area.
12. Bolt Hole:
==========
Bolt hole = Nominal Diameter + 1/8"
= 3/4" + 1/8"
= 0.75 + 0.125
= 0.875"
13. Net Area - Angle:
================
2 Angles 3" leg
A = (2) (15/16) ( 3 - 3/4" - 1/8)"
Thickness Bolt Extra
Angle
A = (2) (0.9375) (3 - 0.875)
A = 1.328 square inches
14. Stress in Net Section:
==================
ft = 54/ 1.328 = 40.7 ksi
15. Allowable Stress on Net Area:
=========================
Table 8.1 P&A 267
Allowable Stress on net area
F t = 0.50 x Fu
F t = 0.50 x 58
= 29 ksi
Note: you use Fu not Fy!
common mistake students make

16. ft> Ft 40.7 ksi > 29 ksi will not work exceeds allowable stress 17. Allowable Stress on Net Area: ========================= Try a higher strength angle Table 8.1 P&A 267 You can get A36 with a Fu of 80 max! See Steel Manual 1-7 Allowable Stress on net area Ft = 0.50 x Fu Ft = 0.50 x 80 Ft = 40 ksi 18. ft> Ft 40.7 ksi > 40 ksi The stress seems a bit high. We may want to increase the thickness from 5/16" to 3/8" 19. Double Angle: ============== Table 4.2 P&A 174 3 x 2 x 3/8 selected Area = 1.73 sq. in.

20. Critical Area: ============ single row of bolts critical area will be at cross-section 21. Stress on unreduced area: ===================== Table 8.1 P&A 267 Ft = 0.60 Fy Ft = 0.60 x 36 ksi Ft = 22 ksi 22. Unreduced Area: =============== A = P/Ft A = 54 / 22 A = 2.46 sq.in. 23. Trial Sections: ============= 3/8" x 7" = 0.375 x 7 =2.625 sq. in. 24. Trial Sections: ============= 1/2" x 5" = 2.5 sq. inch
Table 11.2 P&A 345 Pitch & Edge Distance Table 11.4 P&A 347 Min. Pitch edge distance = 1.5 " angle edge distance = 1.75" plate s pitch = 3" angle/plate g gage = 1.25" angle gap = 0.5" between angles










