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Design of a bolted Framed Beam Connection P&A 354 Typical bolted framing connections P&A 355 Bolted connections for special situations 357 Framed Beam Connections: ==================== 1. Type of Fastening bolt type angle welded to beam 2. Number of Fasteners web bolts in double shear column bolts in single shear number used on beam web 3. Size of Angles depends on size of fasteners magnitude of load size of the supports 4. Length of Angles function of size of fasteners 1.25" edge distance typical 3" pitch typical, refer to table 11.2 angle length min. 1/2 beam depth

Problem: A beam consists of a W27x84 of A36 steel with Fu = 58 ksi, that is needed to develop an end reaction of 80 kips. Design a standard framed beam connection with A 325 F bolts and angles of A36 steel
1. bolted connection 2. standard framed connection 3. 80 kips end reaction 4. A 36 steel angle 5. A 325 F bolts A 325 = high-strength bolt F = denotes bolt for which the limiting resistance is that of friction P&A 342 = definition P&A 344 = Capacity
B. Asked: 1. Number of Bolts 2. Bolt Diameter 3. Angle Thickness 4. Angle Length


Shear Capacity of Bolts 80 kips min. n = 5 min. number of bolts n = 7 max. number of bolts n = 6, 3/4" bolts, angle 1/4", load 92.8 kips n = 5, 7/8" bolts, angle 5/16", load 105 kips No other criterion given we select 7/8" bolts. 2. Bearing on the beam web Table 4.1 P&A 170

W27 W27 = web t = 0.460 inch Total bearing capacity of 5 bolts bolt diameter = 7/8" = 0.875" Fu given = 58 ksi V = n x (bolt diameter) x (web t) x 1.5 Fu V = 5 x 0.875 x 0.460 x 1.5 x 58 V = 175.1 kips 175.1 > 80 kips the total bearing capacity of the bolts is larger than the required load of 80 kips. 3. Shear stress in the net section of the web: Figure 11.11 b or d P&A 355

w = beam depth - ( n x bolt diameter) Beam Depth from Table 4.1 P&A 170 = 26.92" w = beam depth - ( n x bolt diameter) bolt diameter = 7/8" + 1/16" = 0.875 + 0.0625 = 0.9 375 w = 26.92"- (5 x0.9375") w = 22.23 in Stress due to the load: fv = Load / net depth x web thickness fv = 80 / 22.23 x 0.460 fv = 7.82 ksi Allowable shear: Table 8.1 P&A 266

Shear at reduced section = 0.40 Fy = 0.40 x 36 = 14.4 ksi 7.82 ksi < 14.4 ksi The actual shear 7.82 ksi is less than the allowable 14.4 ksi 4. Block Shear = Tearing of the web end Combination of tear stress and tension stress Table 8.1 P&A 266

allowable = 0.30 Fu for shear allowable = 0.50 Fu for tension For tension resistance: w = net cross section w = edge distance - 1/2 diameter w = 2.25" - 0.9375/2 w = 1.78" For shear resistance: w = edge distance - diameters of bolts w = 14" - 4.5 x 0.9375 w = 9.78" For the total resisting force: V = [(tension w x tw) x (0.50 Fu)] + [(shear w x tw) x (0.30 Fu)] V = (1.78 x 0.46 x 29) + (9.78 x 0.46 x 17.4) = 23.7 + 78.3 = 102 kips
E. ANSWER
Because this potential total resistance exceeds the load required, the tearing is not critical.
IRONWORKERS: ============= Members of a Raising Gang: ==================== 1. Pusher - Foreman 2. Connector 3. Tag-Line Man 4. Down-Man 5. Engineer 6. Hocker-on 7. Bolt-Stick Man
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